电路与电子学问题,请求解答
(1) URC = 12 - UCE = 6V
Ic = 6/3K = 2mA
Ib = 2/100 = 0.02ma
Rb = (12-0.7)/0.02ma - 1k = 565k
(2)A^ = -100 = (beita)*RL^/Rbe
1/Rc + 1/RL^ = 1
RL = 1.5K
1,6/3k/100等于20ua,(12-0.7)/20ua等于565k
2,负载电阻是6k