int a = 10000 b c = BITS * 7 / 2 d e f[BITS * 7 / 2 + 1] g;
int main() { for ( ; b - c; ) f[b++] = a / 5; for ( ; d = 0 g = c * 2; c -= 14 printf ("%.4d"e + d / a) e = d % a) for (b = c; d += f[b] * a f[b] = d % -- g d /= g-- --b; d *= b); return 0; }