规格书中这么写的：
The 4K EEPROM only uses the A2 and A1 device address bits with the third bit being a memory page address bit. The two device address bits must compare to their corre-sponding hardwired input pins. The A0 pin is no connect.
就是说，24C04的地址线只关心A2和A1，A0不关心。
0XA0+((WriteAddr/256)<<1这种写法真的很美妙。
假如我用两枚24C02挂在一个I2C总线上，只是一个A2~A0编址000另一个编址001那么恰好可以在两个芯片间无缝存贮。
至于你的问题，只有一枚24C04，就不用担心它了。同时挂两枚04，而一个编址000，另一个编址001，那才会出问题。
