课程设计中的程序代码注释

中国银川

• 2016-12-22

做的课程设计要求用c语言，但写完后太长，大神能给每一行都做一下注释吗？#include <AT89X52.H> unsigned char ps[]={1,2,3,4,5}; unsigned char code dispbit[]={0xfe,0xfd,0xfb,0xf7, 无符号字符型，下同均为1个字节，能够被直接存储在RAM中， 0xef,0xdf,0xbf,0x7f}; 可以存储在0～0x7f区域 unsigned char code dispcode[]={0x3f,0x06,0x5b,0x4f,0x66, 也可以存储在0x80～0xff区域， 0x6d,0x7d,0x07,0x7f,0x6f, 与变量的定义有关。 0x77,0x7c,0x39,0x5e,0x79,0x71, 0x00,0x40,0x73,0xff}; unsigned char dispbuf[8]={18,16,16,16,16,16,16,16}; unsigned char dispcount; unsigned char flashcount; unsigned char temp; unsigned char key; unsigned char keycount; unsigned char pslen=5; unsigned char getps[6]; bit keyoverflag; bit errorflag; bit rightflag; unsigned int second3; unsigned int aa,bb; unsigned int cc; bit okflag; bit alarmflag; bit hibitflag; unsigned char oka,okb; void main(void) { unsigned char i,j; TMOD=0x01; TH0=(65536-500)/256; TL0=(65536-500)%256; TR0=1; ET0=1; EA=1; while(1) { P3=0xff; P3_4=0; temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { for(i=10;i>0;i--) for(j=248;j>0;j--); temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { temp=P3; temp=temp & 0x0f; switch(temp) { case 0x0e: key=7; break; case 0x0d: key=8; break; case 0x0b: key=9; break; case 0x07: key=10; break; } temp=P3; P1_1=~P1_1; if((key>=0) && (key<10)) { if(keycount<6) { getps[keycount]=key; dispbuf[keycount+2]=19; } keycount++; if(keycount==6) { keycount=6; } else if(keycount>6) { keycount=6; keyoverflag=1;//key overflow } } else if(key==12)//delete key { if(keycount>0) { keycount--; getps[keycount]=0; dispbuf[keycount+2]=16; } else { keyoverflag=1; } } else if(key==15)//enter key { if(keycount!=pslen) { errorflag=1; rightflag=0; second3=0; } else { for(i=0;i<keycount;i++) { if(getps[i]!=ps[i]) { i=keycount; errorflag=1; rightflag=0; second3=0; goto a; } } errorflag=0; rightflag=1; a: i=keycount; } } temp=temp & 0x0f; while(temp!=0x0f) { temp=P3; temp=temp & 0x0f; } keyoverflag=0;//????????? } } P3=0xff; P3_5=0; temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { for(i=10;i>0;i--) for(j=248;j>0;j--); temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { temp=P3; temp=temp & 0x0f; switch(temp) { case 0x0e: key=4; break; case 0x0d: key=5; break; case 0x0b: key=6; break; case 0x07: key=11; break; } temp=P3; P1_1=~P1_1; if((key>=0) && (key<10)) { if(keycount<6) { getps[keycount]=key; dispbuf[keycount+2]=19; } keycount++; if(keycount==6) { keycount=6; } else if(keycount>6) { keycount=6; keyoverflag=1;//key overflow } } else if(key==12)//delete key { if(keycount>0) { keycount--; getps[keycount]=0; dispbuf[keycount+2]=16; } else { keyoverflag=1; } } else if(key==15)//enter key { if(keycount!=pslen) { errorflag=1; rightflag=0; second3=0; } else { for(i=0;i<keycount;i++) { if(getps[i]!=ps[i]) { i=keycount; errorflag=1; rightflag=0; second3=0; goto a4; } } errorflag=0; rightflag=1; a4: i=keycount; } } temp=temp & 0x0f; while(temp!=0x0f) { temp=P3; temp=temp & 0x0f; } keyoverflag=0;//????????? } } P3=0xff; P3_6=0; temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { for(i=10;i>0;i--) for(j=248;j>0;j--); temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { temp=P3; temp=temp & 0x0f; switch(temp) { case 0x0e: key=1; break; case 0x0d: key=2; break; case 0x0b: key=3; break; case 0x07: key=12; break; } temp=P3; P1_1=~P1_1; if((key>=0) && (key<10)) { if(keycount<6) { getps[keycount]=key; dispbuf[keycount+2]=19; } keycount++; if(keycount==6) { keycount=6; } else if(keycount>6) { keycount=6; keyoverflag=1;//key overflow } } else if(key==12)//delete key { if(keycount>0) { keycount--; getps[keycount]=0; dispbuf[keycount+2]=16; } else { keyoverflag=1; } } else if(key==15)//enter key { if(keycount!=pslen) { errorflag=1; rightflag=0; second3=0; } else { for(i=0;i<keycount;i++) { if(getps[i]!=ps[i]) { i=keycount; errorflag=1; rightflag=0; second3=0; goto a3; } } errorflag=0; rightflag=1; a3: i=keycount; } } temp=temp & 0x0f; while(temp!=0x0f) { temp=P3; temp=temp & 0x0f; } keyoverflag=0;//????????? } } P3=0xff; P3_7=0; temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { for(i=10;i>0;i--) for(j=248;j>0;j--); temp=P3; temp=temp & 0x0f; if (temp!=0x0f) { temp=P3; temp=temp & 0x0f; switch(temp) { case 0x0e: key=0; break; case 0x0d: key=13; break; case 0x0b: key=14; break; case 0x07: key=15; break; } temp=P3; P1_1=~P1_1; if((key>=0) && (key<10)) { if(keycount<6) { getps[keycount]=key; dispbuf[keycount+2]=19; } keycount++; if(keycount==6) { keycount=6; } else if(keycount>6) { keycount=6; keyoverflag=1;//key overflow } } else if(key==12)//delete key { if(keycount>0) { keycount--; getps[keycount]=0; dispbuf[keycount+2]=16; } else { keyoverflag=1; } } else if(key==15)//enter key { if(keycount!=pslen) { errorflag=1; rightflag=0; second3=0; } else { for(i=0;i<keycount;i++) { if(getps[i]!=ps[i]) { i=keycount; errorflag=1; rightflag=0; second3=0; goto a2; } } errorflag=0; rightflag=1; a2: i=keycount; } } temp=temp & 0x0f; while(temp!=0x0f) { temp=P3; temp=temp & 0x0f; } keyoverflag=0;//????????? } } } } void t0(void) interrupt 1 using 0 { TH0=(65536-500)/256; TL0=(65536-500)%256; flashcount++; if(flashcount==8) { flashcount=0; P0=dispcode[dispbuf[dispcount]]; P2=dispbit[dispcount]; dispcount++; if(dispcount==8) { dispcount=0; } } if((errorflag==1) && (rightflag==0)) { bb++; if(bb==800) { bb=0; alarmflag=~alarmflag; } if(alarmflag==1)//sound alarm signal { P1_7=~P1_7; } aa++; if(aa==800)//light alarm signal { aa=0; P1_0=~P1_0; } second3++; if(second3==6400) { second3=0; errorflag=0; rightflag=0; alarmflag=0; bb=0; aa=0; } } else if((errorflag==0) && (rightflag==1)) { P1_0=0; cc++; if(cc<1000) { okflag=1; } else if(cc<2000) { okflag=0; } else { errorflag=0; rightflag=0; P1_7=1; cc=0; oka=0; okb=0; okflag=0; P1_0=1; } if(okflag==1) { oka++; if(oka==2) { oka=0; P1_7=~P1_7; } } else { okb++; if(okb==3) { okb=0; P1_7=~P1_7; } } } if(keyoverflag==1) { P1_7=~P1_7; } } 4×4键盘及8位数码管显示构成的电子密码锁